abstract algebra - radical of an ideal: $\sqrt{IJ}$ $=$ $\sqrt{I}\sqrt{J}$ $=$ $\sqrt{I}\cap\sqrt{J}$ $=$ $\sqrt{I\cap J}$? - Mathematics Stack Exchange
sqrt(i) - YouTube
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What is the value of [math]\sqrt{i}+\sqrt{-i}[/math] (where [math]i=\sqrt{-1}[/math])? - Quora
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sqrt(i) - YouTube
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Square root of i - YouTube
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