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One mole of an ideal gas undergoes a process P=P0/(2+V0/V),(where P0 and V0 are constant).Change in temperature of the gas when volume is changed from V =V0 to V =3V0 is
The velocity of a particle is v = v0 + gt + ft^2 . If its position is x = 0 at t = 0, then its displacement after unit time (t = 1) is:
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The velocity of a particle is v = v0 + gt + ft^2 . If its position is x = 0 at t = 0, then its displacement after unit time (t = 1) is:
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The rms value of potential difference V shown in figure is :